3x^2-10x^2+x+6=0

Solution for 3x^2-10x^2+x+6=0 equation:

3x^2-10x^2+x+6=0

We add all the numbers together, and all the variables

-7x^2+x+6=0

a = -7; b = 1; c = +6;
Δ = b2-4ac
Δ = 12-4·(-7)·6
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-13}{2*-7}=\frac{-14}{-14}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+13}{2*-7}=\frac{12}{-14}
=-6/7
$